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[学习交流] CCNA640-802 V13题库试题分析13(艾迪飞吴老师讲解) [复制链接]

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发表于 2007-11-26 19:57:19 |显示全部楼层

1．What is the purpose of the command shown below? 
vtp password Fl0r1da 
A. It is used to validate the sources of VTP advertisements sent between switches. 
B. It is used to access the VTP server to make changes to the VTP configuration. 
C. It allows two VTP servers to exist in the same domain, each configured with different passwords. 
D. It is the password required when promoting a switch from VTP client mode to VTP server mode. 
E. It is used to prevent a switch newly added to the network from sending incorrect VLAN information to the other switches in the domain. 
Answer: A
解释一下：VTP的密码是为了保证在同一个domain里的交换机的安全，在同一个domain里交换机只有密码相同了才可以相互传递VLAN的信息。
<?xml:namespace prefix = o ns = "urn:schemas-microsoft-com:office:office" /><o:p> </o:p>
2．A network administrator is configuring the routers in the graphic for OSPF. The OSPF process has been started and the networks have been configured for Area 0 as shown in the diagram. The network administrator has several options for configuring Router B to ensure that it will be preferred as the designated router (DR) for the 172.16.1.0/24 LAN segment. What configuration tasks could be used to establish this preference? (Choose three.)
<o:p>

2.jpg (30.8 KB, 下载次数: 5) </o:p>
<?xml:namespace prefix = v ns = "urn:schemas-microsoft-com:vml" /><v:shapetype id=_x0000_t75 coordsize="21600,21600" o:spt="75" o:preferrelative="t" path="m@4@5l@4@11@9@11@9@5xe" filled="f" stroked="f"><v:stroke joinstyle="miter"></v:stroke><v:formulas><v:f eqn="if lineDrawn pixelLineWidth 0"></v:f><v:f eqn="sum @0 1 0"></v:f><v:f eqn="sum 0 0 @1"></v:f><v:f eqn="prod @2 1 2"></v:f><v:f eqn="prod @3 21600 pixelWidth"></v:f><v:f eqn="prod @3 21600 pixelHeight"></v:f><v:f eqn="sum @0 0 1"></v:f><v:f eqn="prod @6 1 2"></v:f><v:f eqn="prod @7 21600 pixelWidth"></v:f><v:f eqn="sum @8 21600 0"></v:f><v:f eqn="prod @7 21600 pixelHeight"></v:f><v:f eqn="sum @10 21600 0"></v:f></v:formulas><v:path o:extrusionok="f" gradientshapeok="t" o:connecttype="rect"></v:path><o:lock v:ext="edit" aspectratio="t"></o:lock></v:shapetype>
A. Configure the priority value of the Fa0/0 interface of RouterB to a higher value than any other interface on theEthernet network.<o:p></o:p>
B. Change the router id of Router B by assigning the IP address 172.16.1.130/24 to the Fa0/0 interface of RouterB.<o:p></o:p>
C. Configure a loopback interface on RouterB with an IP address higher than any IP address on the other routers. <o:p></o:p>
D. Change the priority value of the Fa0/0 interface of RouterB to zero. <o:p></o:p>
E. Change the priority values of the Fa0/0 interfaces of RouterA and RouterC to zero.<o:p></o:p>
F. No further configuration is necessary.<o:p></o:p>
Answer: ACE<o:p></o:p>
解释一下：OSPF中的共享介质下是需要选举DR和BDR的，而这个选举的过程是通过比较优先级和RID来实现的。优先级越高的越优先选举成为DR，优先级为0的接口是不参加DR的选举的，如果优先级相同就比较他们的RID,RID越大的越优先。RID的选举过程是：手工指定的最为优先，如果没有手工指定RID，则比较路由器上活动接口的IP地址，如果有回环口就选用回环口IP地址最大的地址作为RID,如果没有回环口，就选用物理接口地址中最大的IP地址为RID<o:p></o:p>
这个题中需要确保Router B成为网络172.16.1.0/24的DR，根据上面的解释可以看出，让他成为DR的方式有：改Router B的f0/0的优先级为最大的；改172.16.1.0/24网段上的其他接口的优先级为0;设置Router B的RID最大。<o:p></o:p>
<o:p>

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[学习交流] CCNA640-802 V13题库试题分析13(艾迪飞吴老师讲解) [复制链接]

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